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For determining how many pounds of force a gas strut needs to be to give a 5-7 pound pull/push force on a control wheel that is 25" above the pivot fulcrum and the strut is mounted 3" below the pivot fulcrum?

I don't know what strength of strut to buy because I don't know this formula.

Hehe... I tried calculating my own gas struts for the yoke and ended on 200nm on a single system, but this was after folding a lot of papers, saying "... to he** with it, I'll try the 200s", and came out fine :) :)

See if you understand:
http://en.wikipedia.org/wiki/Lever (http://en.wikipedia.org/wiki/Lever)

Well, I understand the principles of the explanation, but I don't know how to plug the figures into the formula to arrive at the solution.

Load arm X Load Force = Effort arm X Effort Force

3" X 60Lbs (for example) = 25" x ?????

I don't understand how to arrive at the effort force knowing the first three variables.

Thanks for posting that. Maybe a math major here can help.

Think of it in terms of force ie 3" x 60lbs  = 180 in/lbs. So in your example, if you have a moment arm of 25" then to achieve the same force then you need a weight or effort of 180lbs divided by 25" - which equates to circa 7lbs.

Regards

David

Thanks for helping out with that.

Welcome to the forum. Out new resident math major!  :idiot:

1 + 1 = 4 right?  I am not a math major by far.. Good to know we have someone here that is good with numbers...

Trev